Suppose that the student IQ scores form a normal distribution with mean v=100 and standard deviation σ=20. Find the percentage P of students whose scores fall between: (a) 80 and 120 , (b) 60 and 140, (c) 40 and 160 , (d) 100 and 120, (e) over 160, (f) le (2024)

`); let searchUrl = `/search/`; history.forEach((elem) => { prevsearch.find('#prevsearch-options').append(`

${elem}

`); }); } $('#search-pretype-options').empty(); $('#search-pretype-options').append(prevsearch); let prevbooks = $(false); [ {title:"Recently Opened Textbooks", books:previous_books}, {title:"Recommended Textbooks", books:recommended_books} ].forEach((book_segment) => { if (Array.isArray(book_segment.books) && book_segment.books.length>0 && nsegments<2) { nsegments+=1; prevbooks = $(`

  • ${book_segment.title}
  • `); let searchUrl = "/books/xxx/"; book_segment.books.forEach((elem) => { prevbooks.find('#prevbooks-options'+nsegments.toString()).append(`

    ${elem.title} ${ordinal(elem.edition)} ${elem.author}

    `); }); } $('#search-pretype-options').append(prevbooks); }); } function anon_pretype() { let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_ANON')); }catch(e) {} if ('previous_books' in prebooks && 'recommended_books' in prebooks) { previous_books = prebooks.previous_books; recommended_books = prebooks.recommended_books; if (typeof PREVBOOKS !== 'undefined' && Array.isArray(PREVBOOKS)) { new_prevbooks = PREVBOOKS; previous_books.forEach(elem => { for (let i = 0; i < new_prevbooks.length; i++) { if (elem.id == new_prevbooks[i].id) { return; } } new_prevbooks.push(elem); }); new_prevbooks = new_prevbooks.slice(0,3); previous_books = new_prevbooks; } if (typeof RECBOOKS !== 'undefined' && Array.isArray(RECBOOKS)) { new_recbooks = RECBOOKS; for (let j = 0; j < new_recbooks.length; j++) { new_recbooks[j].viewed_at = new Date(); } let insert = true; for (let i=0; i < recommended_books.length; i++){ for (let j = 0; j < new_recbooks.length; j++) { if (recommended_books[i].id == new_recbooks[j].id) { insert = false; } } if (insert){ new_recbooks.push(recommended_books[i]); } } new_recbooks.sort((a,b)=>{ adate = new Date(2000, 0, 1); bdate = new Date(2000, 0, 1); if ('viewed_at' in a) {adate = new Date(a.viewed_at);} if ('viewed_at' in b) {bdate = new Date(b.viewed_at);} // 100000000: instead of just erasing the suggestions from previous week, // we just move them to the back of the queue acurweek = ((new Date()).getDate()-adate.getDate()>7)?0:100000000; bcurweek = ((new Date()).getDate()-bdate.getDate()>7)?0:100000000; aviews = 0; bviews = 0; if ('views' in a) {aviews = acurweek+a.views;} if ('views' in b) {bviews = bcurweek+b.views;} return bviews - aviews; }); new_recbooks = new_recbooks.slice(0,3); recommended_books = new_recbooks; } localStorage.setItem('PRETYPE_BOOKS_ANON', JSON.stringify({ previous_books: previous_books, recommended_books: recommended_books })); build_popup(); } } var whiletyping_search_object = null; var whiletyping_search = { books: [], curriculum: [], topics: [] } var single_whiletyping_ajax_promise = null; var whiletyping_database_initial_burst = 0; //number of consecutive calls, after 3 we start the 1 per 5 min calls function get_whiletyping_database() { //gets the database from the server. // 1. by validating against a local database value we confirm that the framework is working and // reduce the ammount of continuous calls produced by errors to 1 per 5 minutes. return localforage.getItem('whiletyping_last_attempt').then(function(value) { if ( value==null || (new Date()) - (new Date(value)) > 1000*60*5 || (whiletyping_database_initial_burst < 3) ) { localforage.setItem('whiletyping_last_attempt', (new Date()).getTime()); // 2. Make an ajax call to the server and get the search database. let databaseUrl = `/search/whiletype_database/`; let resp = single_whiletyping_ajax_promise; if (resp === null) { whiletyping_database_initial_burst = whiletyping_database_initial_burst + 1; single_whiletyping_ajax_promise = resp = new Promise((resolve, reject) => { $.ajax({ url: databaseUrl, type: 'POST', data:{csrfmiddlewaretoken: "HB4EzMOjz7c05gytipZQZia0rHndiuXhapTcUIzHNXjK49rLobGi6tw8879g4RJp"}, success: function (data) { // 3. verify that the elements of the database exist and are arrays if ( ('books' in data) && ('curriculum' in data) && ('topics' in data) && Array.isArray(data.books) && Array.isArray(data.curriculum) && Array.isArray(data.topics)) { localforage.setItem('whiletyping_last_success', (new Date()).getTime()); localforage.setItem('whiletyping_database', data); resolve(data); } }, error: function (error) { console.log(error); resolve(null); }, complete: function (data) { single_whiletyping_ajax_promise = null; } }) }); } return resp; } return Promise.resolve(null); }).catch(function(err) { console.log(err); return Promise.resolve(null); }); } function get_whiletyping_search_object() { // gets the fuse objects that will be in charge of the search if (whiletyping_search_object){ return Promise.resolve(whiletyping_search_object); } database_promise = localforage.getItem('whiletyping_database').then(function(database) { return localforage.getItem('whiletyping_last_success').then(function(last_success) { if (database==null || (new Date()) - (new Date(last_success)) > 1000*60*60*24*30 || (new Date('2023-04-25T00:00:00')) - (new Date(last_success)) > 0) { // New database update return get_whiletyping_database().then(function(new_database) { if (new_database) { database = new_database; } return database; }); } else { return Promise.resolve(database); } }); }); return database_promise.then(function(database) { if (database) { const options = { isCaseSensitive: false, includeScore: true, shouldSort: true, // includeMatches: false, // findAllMatches: false, // minMatchCharLength: 1, // location: 0, threshold: 0.2, // distance: 100, // useExtendedSearch: false, ignoreLocation: true, // ignoreFieldNorm: false, // fieldNormWeight: 1, keys: [ "title" ] }; let curriculum_index={}; let topics_index={}; database.curriculum.forEach(c => curriculum_index[c.id]=c); database.topics.forEach(t => topics_index[t.id]=t); for (j=0; j

    Solutions
  • Textbooks
  • `); } function build_solutions() { if (Array.isArray(solution_search_result)) { const viewAllHTML = userSubscribed ? `View All` : ''; var solutions_section = $(`
  • Solutions ${viewAllHTML}
  • `); let questionUrl = "/questions/xxx/"; let askUrl = "/ask/question/xxx/"; solution_search_result.forEach((elem) => { let url = ('course' in elem)?askUrl:questionUrl; let solution_type = ('course' in elem)?'ask':'question'; let subtitle = ('course' in elem)?(elem.course??""):(elem.book ?? "")+"    "+(elem.chapter?"Chapter "+elem.chapter:""); solutions_section.find('#whiletyping-solutions').append(` ${elem.text} ${subtitle} `); }); $('#search-solution-options').empty(); if (Array.isArray(solution_search_result) && solution_search_result.length>0){ $('#search-solution-options').append(solutions_section); } MathJax.typesetPromise([document.getElementById('search-solution-options')]); } } function build_textbooks() { $('#search-pretype-options').empty(); $('#search-pretype-options').append($('#search-solution-options').html()); if (Array.isArray(textbook_search_result)) { var books_section = $(`
  • Textbooks View All
  • `); let searchUrl = "/books/xxx/"; textbook_search_result.forEach((elem) => { books_section.find('#whiletyping-books').append(` ${elem.title} ${ordinal(elem.edition)} ${elem.author} `); }); } if (Array.isArray(textbook_search_result) && textbook_search_result.length>0){ $('#search-pretype-options').append(books_section); } } function build_popup(first_time = false) { if ($('#search-text').val()=='') { build_pretype(); } else { solution_and_textbook_search(); } } var search_text_out = true; var search_popup_out = true; const is_login = false; const user_hash = null; function pretype_setup() { $('#search-text').focusin(function() { $('#search-popup').addClass('show'); resize_popup(); search_text_out = false; }); $( window ).resize(function() { resize_popup(); }); $('#search-text').focusout(() => { search_text_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-popup').mouseenter(() => { search_popup_out = false; }); $('#search-popup').mouseleave(() => { search_popup_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-text').on("keyup", delay(() => { build_popup(); }, 200)); build_popup(true); let prevbookUrl = `/search/pretype_books/`; let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_'+(is_login?user_hash:'ANON'))); }catch(e) {} if (prebooks && 'previous_books' in prebooks && 'recommended_books' in prebooks) { if (is_login) { previous_books = prebooks.previous_books; recommended_books = prebooks.recommended_books; if (prebooks.time && new Date().getTime()-prebooks.time<1000*60*60*6) { build_popup(); return; } } else { anon_pretype(); return; } } $.ajax({ url: prevbookUrl, method: 'POST', data:{csrfmiddlewaretoken: "HB4EzMOjz7c05gytipZQZia0rHndiuXhapTcUIzHNXjK49rLobGi6tw8879g4RJp"}, success: function(response){ previous_books = response.previous_books; recommended_books = response.recommended_books; if (is_login) { localStorage.setItem('PRETYPE_BOOKS_'+user_hash, JSON.stringify({ previous_books: previous_books, recommended_books: recommended_books, time: new Date().getTime() })); } build_popup(); }, error: function(response){ console.log(response); } }); } $( document ).ready(pretype_setup); $( document ).ready(function(){ $('#search-popup').on('click', '.search-view-item', function(e) { e.preventDefault(); let autoCompleteSearchViewUrl = `/search/autocomplete_search_view/`; let objectUrl = $(this).attr('href'); let selectedId = $(this).data('objid'); let searchResults = []; $("#whiletyping-solutions").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $("#whiletyping-books").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $.ajax({ url: autoCompleteSearchViewUrl, method: 'POST', data:{ csrfmiddlewaretoken: "HB4EzMOjz7c05gytipZQZia0rHndiuXhapTcUIzHNXjK49rLobGi6tw8879g4RJp", query: $('#search-text').val(), searchObjects: JSON.stringify(searchResults) }, dataType: 'json', complete: function(data){ window.location.href = objectUrl; } }); }); });
    Suppose that the student IQ scores form a normal distribution with mean v=100 and standard deviation σ=20. Find the percentage P of students whose scores fall between: (a) 80 and 120 , (b) 60 and 140, (c) 40 and 160 , (d) 100 and 120, (e) over 160, (f) le (2024)

    FAQs

    When IQ scores are normally distributed having a mean of 100 and a standard deviation of 15? ›

    We know that a normal distribution has the property that approximately 68% of the data falls within one standard deviation of the mean, so in this case, approximately 68% of IQ scores fall between 85 (100 - 15) and 115 (100 + 15).

    What is the normal distribution of IQ scores with U 100 and O 15? ›

    IQ scores form a normal distribution with u = 100 and o = 15. Individuals with IQs betweeen 90 and 110 are classified as average.

    How many standard deviations is an IQ of 70 from the mean 100? ›

    IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. About 68% of individuals have IQ scores in the interval 100 ± 1 ( 15 ) = [ 85 , 115 ] . About 95% of individuals have IQ scores in the interval 100 ± 2 ( 15 ) = [ 70 , 130 ] .

    Do IQ scores have a normal distribution with a mean of 100? ›

    One example of a variable that has a Normal distribution is IQ. In the population, the mean IQ is 100 and it standard deviation, depending on the test, is 15 or 16. If a large enough random sample is selected, the IQ distribution of the sample will resemble the Normal curve.

    How many standard deviations below the mean IQ score of 100 indicates an IQ score in the intellectually disabled range? ›

    IQ test results fall along the normal (bell-shaped) curve, with an average IQ of 100, and individuals who are intellectually disabled are usually two standard deviations below the average (IQ below 70).

    What is the normal distribution of IQ scores? ›

    e.g. IQ is normally distributed (mean = 100, SD = 15). 68% of people have IQs between 85 and 115 (100 +/- 15). 95% have IQs between 70 and 130 (100 +/- (2*15). 99.7% have IQs between 55 and 145 (100 +/- (3*15).

    What does a score of 100 on the normal distribution of intelligence scores mean? ›

    On many tests, a score of 100 is considered the average IQ. Sixty-eight percent of scores fall within one standard deviation of the mean (that is, between 85 and 115). That means that nearly 70% of all people score within plus or minus 15 points of the average score.

    What intelligent quotient IQ scores form a normal distribution with U 100? ›

    IQ scores form a normal distribution with u=100 and 0=15. Individuals with IQs between 90 and 110 are classified as average.

    What is the distribution of IQ levels? ›

    Stanford–Binet Intelligence Scale Fifth Edition
    IQ Range ("deviation IQ")IQ Classification
    130–140Gifted or very advanced
    120–129Superior
    110–119High average
    90–109Average
    5 more rows

    When scores on an intelligence test form a normal curve with a standard deviation of 15? ›

    For modern IQ tests, the raw score is transformed to a normal distribution with mean 100 and standard deviation 15. This results in approximately two-thirds of the population scoring between IQ 85 and IQ 115 and about 2 percent each above 130 and below 70. Scores from intelligence tests are estimates of intelligence.

    What is the standard deviation of the normal distribution in an IQ test? ›

    An example of a standardized normal distribution is the Intelligence Quotient or 'IQ” score. The mean (μ) IQ score for the entire population is 100. The standard deviation (σ) is 15 points.

    What is the deviation from the mean IQ? ›

    In this system of scores, approximately 68% of IQ scores fall within one standard deviation from the mean (i.e., between 85 and 115), and approximately 95% of scores fall within two standard deviations of the mean (i.e., between 70 and 130).

    What is the average IQ for a normally distributed population of individuals? ›

    In general, an IQ score is defined with a median and mean of 100. Scores above 130 are labeled as above average or “very superior,” while scores under 70 would be considered below average or labeled as “borderline impaired.” Most people have an average IQ between 85 and 115.

    Why is IQ not normally distributed? ›

    It has been an empirically observed fact that many "naturally" observed traits, like height or IQ, are NOT empirically normally distributed. At the very least they can't be truly normally distributed because they are always non-negative.

    What is the mean of the normal distribution in an IQ test quizlet? ›

    In a standardized IQ test, scores were normally distributed, with a mean score of 100 and a standardized deviation of 15.

    What is the mean and standard deviation of an IQ score? ›

    The mean (μ) IQ score for the entire population is 100. The standard deviation (σ) is 15 points. If you have an IQ score of 115 (100 + 15), then you are 1 standard deviation above the mean (z = +1). If you have an IQ score of 85 (100 – 15), then you are 1 standard deviation below the mean (z = -1).

    Is the distribution of IQ approximately normal in shape with a mean of 100 and a standard deviation of 15? ›

    In this case the mean is 100, and the standard deviation is 15; therefore, approximately 99.7% of the observations (IQ scores) fall between 100 − 3 * 15 and 100 + 3 * 15 or between 55 and 145. Approximately 100% − 99.7% = 0.3% of the observations fall outside this interval.

    How many standard deviations above the mean is an IQ score of 130? ›

    So a person with a 130 IQ (on a test with a mean of 100 and a standard deviation of 15) is two standard deviations above the mean. This is approximately in the top 2% of scores.

    References

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